By Larry M. Hyman

*without*syllables.

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**Sample text**

At ﬁrst sight, this is a bit trickier since we somehow have to make sure that ψ could not have been obtained by any sequence of construction rules. Let us look at the formula (¬)() ∨ pq → from above. We can decide this matter by being very observant. ); but the only time we can put a ‘)’ to the right of something is if that something is a well-formed formula (again, check all the rules to see that this is so). Thus, (¬)() ∨ pq → is not well-formed. Probably the easiest way to verify whether some formula φ is well-formed is by trying to draw its parse tree.

And p1 , p2 , p3 , . . is a wellformed formula. ¬: If φ is a well-formed formula, then so is (¬φ). ∧: If φ and ψ are well-formed formulas, then so is (φ ∧ ψ). ∨: If φ and ψ are well-formed formulas, then so is (φ ∨ ψ). →: If φ and ψ are well-formed formulas, then so is (φ → ψ). It is most crucial to realize that this deﬁnition is the one a computer would expect and that we did not make use of the binding priorities agreed upon in the previous section. Convention. In this section we act as if we are a rigorous computer and we call formulas well-formed iﬀ they can be deduced to be so using the deﬁnition above.

The deﬁnition of k l with l ≥ 0). Sentence (3) on page 2 suggests there may be true properties M (n) for which mathematical induction won’t work. Course-of-values induction. There is a variant of mathematical induction in which the induction hypothesis for proving M (n + 1) is not just M (n), but the conjunction M (1) ∧ M (2) ∧ · · · ∧ M (n). In that variant, called courseof-values induction, there doesn’t have to be an explicit base case at all – everything can be done in the inductive step. How can this work without a base case?

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